How fast is the edge of the yo-yo spinning in mph

Click For Summary
SUMMARY

The exercise involves calculating the linear speed of a yo-yo with a diameter of 2.25 inches spinning at 4500 revolutions per minute (RPM). The correct formula for linear velocity is v = r × ω, where r is the radius and ω is the angular velocity. After correcting the radius to 1.125 inches and recalculating, the accurate speed of the yo-yo's edge is determined to be 30.12 miles per hour, confirming that the initial calculation of 32.78 miles per hour was due to a typographical error in the radius.

PREREQUISITES
  • Understanding of linear velocity and angular velocity concepts
  • Familiarity with the relationship between revolutions per minute and angular velocity
  • Basic knowledge of unit conversions, specifically inches to miles
  • Proficiency in using mathematical formulas for speed calculations
NEXT STEPS
  • Study the derivation of angular velocity from revolutions per minute
  • Learn about unit conversions between different measurement systems
  • Explore the application of trigonometric functions in physics problems
  • Practice solving similar problems involving rotational motion and linear speed
USEFUL FOR

Students studying physics, particularly those focusing on rotational motion and speed calculations, as well as educators looking for examples of common mistakes in problem-solving.

Vital
Messages
108
Reaction score
4

Homework Statement


Hello!
I am trying to solve the exercise, but I don't see my mistakes - I can't come up with a correct answer.
The exercise from the begging of trigonometry, so it has to be solved using concepts of a speed and angular velocity.

A yo-yo which is 2.25 inches in diameter spins at a rate of 4500 revolutions per minute. How

fast is the edge of the yo-yo spinning in miles per hour? Round your answer to two decimal

places.

Homework Equations


Here is how I am trying to solve it:
v = r x w,
where v is the speed, r radius, w is the average angular velocity, which equals to

w = 2π x f, where f is the frequency of revolutions and equals to number of revolutions / time

The Attempt at a Solution


Putting it all together I get:

r = 2.250 / 2 = 1.225
number of revolutions in one hour 4500 х 60 = 270 000
w = 2π × 270 000 = 1 695 600
v = 1.225 x 1 695 600 = 2 077 110 inches in one hour

Convert to miles:
2 077 110 / 63 360 = 32.78 miles per hour

But it should be 30.12 miles per hour.

Please, help me to find my mistake.
Thank you!
 
Physics news on Phys.org
Hello Vital, :welcome:

It is always a good idea to estimate answers before typing them in on a calculator
But in this case it may have been a simple oversight ?
Vital said:
r = 2.250 / 2 = 1.225
No it is not.
 
BvU said:
Hello Vital, :welcome:

It is always a good idea to estimate answers before typing them in on a calculator
But in this case it may have been a simple oversight ?
No it is not.

Oh! Yes. It is a typo, which has gone through all calculations. And I actually do this type of calculations manually (some in mind, and others, with bigger numbers, on paper).
Thank you very much. Indeed an awkward situation. :)
 
New PF member has been reminded not to post solutions to homework. This thread is over a year old, though, so their soltuion will be left visible.
Hello Vital,

Some typo error could be quite annoying, it would be good for others if we could make some corrections to your solution.
I made some definition to some numbers in the question as to make simple.

v = r * ω
v = r * θ/t
v = linear velocity
r = radius
t = time

ω = 4500 revolution per minute
1 minute = 1/60 hour
ω = θ / t
ω = angular velocity

ω = 4500 * 2π radians / 1/60 hour = 540,000 π radians/hour
ω = 540,000 * 3.14 = 1,695,600

d = 2.25 inches
r = d/2 = 2.25/2 = 1.125 inches
63360 inches = 1 mile

r = 1.125/ 63360 miles

linear velocity = r * ω = 1.125/63360 * 1695600 = 1.125 * 26.764 = 30.12

Thank you
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
9K
  • · Replies 5 ·
Replies
5
Views
17K