How Fast is the Top of the Ladder Sliding Down When the Bottom Moves Away?

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The problem involves a 1.9-meter ladder leaning against a vertical wall, with the bottom being pulled away at a speed of 25 cm/s. Using the Pythagorean theorem, the height of the ladder can be expressed as h = √(L² - x²), where L is the length of the ladder and x is the distance from the wall. By differentiating this equation with respect to time, the rate at which the top of the ladder slides down the wall can be calculated. The final answer indicates that the top of the ladder is sliding down at a rate of -17.5 cm/s.

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Homework Statement


laddercopy.png


A 1.9 metre ladder is leaning against a vertical wall. If the bottom of the ladder is 30 cm from the wall and is being pull away from the wall with a horizontal speed of 25 cm per second, how fast is the top of the ladder sliding down the vertical wall?

We define the the direction up the wall to be positive, so that your answer must be negative.

Homework Equations


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does this mean when x=30 cm dx/dt = 25

The Attempt at a Solution


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this means that the wall height is 187.6 cm using pythagoras theorem

Any help will be much appreciated
 
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53Mark53 said:
does this mean when x=30 cm dx/dt = 25
Yes. Start with writing height of the ladder as a function of x.
 
cnh1995 said:
Yes. Start with writing height of the ladder as a function of x.

does this mean

h=x^2+y^2

dx/dt=2x+2y

25=2x30+2y
-35=2y
y=-17.5
 
cnh1995 said:
Yes. Start with writing height of the ladder as a function of x.

I got the answer thanks :)
 
Height of the ladder is h=√(L2-x2), where L=length of the ladder i.e. 1.9m.
You can proceed by taking derivative on both sides w.r.t. time.
 
53Mark53 said:
this means that the wall height is 187.6 cm using pythagoras theorem
The height of the wall is irrelevant to this problem.
 

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