1. The problem statement, all variables and given/known data A 40.5 kg wagon is towed up a hill inclined at 16.5 degrees with respect to the horizontal. The tow rope is parallel to the incline and exerts a force of 125 N on the wagon. Assume that the wagon starts from rest at the bottom of the hill, and disregard friction and significant figures. The acceleration of gravity is 9.81 m/s^2 How fast is the wagon going after moving 82.1 m up the hill? Answer in m/s 2. Relevant equations Force = mass * acceleration Fg = ma Vf^2= 2ad + Vi^2 3. The attempt at a solution 40.5 kg * 9.81 m/s^s = 397.305 kg/m/s^2 or 397.305 N Tilting the time of reference, so that you just need to find the Fg of the diagram. Fg in the x direction = 397.305 cos 16.5 = 380.8438748 Fg in the y direction = 397.305 sin 16.5 = 112.8407165 Just adding the forces in the x direction 380.8438749 - 125 = 255.9438748 255.9438748 / 40.5 kg = 6.319601847 = acceleration in the x direction Acceleration in the y direction = 0 because the wagon isn't moving up and down Vf^2 = 2ad + Vi^2 Vf^2 = 2 (6.3196017847)(82.1) + 0 ^2 Vf^2 = square root of 1037.678623 Vf = 32.21301947 m/s I got 32.21301947 m/s as my answer Did I do anything wrong?