- #1

laurs

- 2

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- Homework Statement
- The two masses are each initially 2.60 m above the ground, and the massless frictionless pulley is 10.00 m above the ground. The masses are m1 = 1.71 kg and m2 = 4.59 kg. What maximum height does the lighter object reach after the system is released?

(Hint: First determine the acceleration of the lighter mass and then its velocity at the moment the heavier one hits the ground.

This is its "launch" speed. Assume it doesn't hit the pulley.)

- Relevant Equations
- a = (m2-m1)(g)/(m2+m1)

vf^2 = vi^2 + 2ad

Fnet = ma

Fg = mg

Magnitude of acceleration of system:

a = (4.59kg - 1.71kg)(9.81N/kg)/(4.59kg + 1.71kg)

= 4.48 m/s^2

Velocity of lighter mass when heavier one hits the ground:

vf^2 = vi^2 + 2ad

= 0 + 2(4.48m/s^2)(2.60m)

vf = 4.83 m/s [up]

I am not sure what to do from here? I don't really understand what the hint means by launch speed, like is the mass flying out of the pulley into a parabolic trajectory?

a = (4.59kg - 1.71kg)(9.81N/kg)/(4.59kg + 1.71kg)

= 4.48 m/s^2

Velocity of lighter mass when heavier one hits the ground:

vf^2 = vi^2 + 2ad

= 0 + 2(4.48m/s^2)(2.60m)

vf = 4.83 m/s [up]

I am not sure what to do from here? I don't really understand what the hint means by launch speed, like is the mass flying out of the pulley into a parabolic trajectory?