How fast must a spaceship travel to reach Alpha Centauri in 10 years?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the speed required for a spaceship to reach Alpha Centauri, which is approximately 4.3 light years away, within a time frame of 10 years as experienced by the crew. The problem involves concepts from special relativity, including time dilation and velocity calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between distance, time, and velocity, with some attempting to apply the concept of time dilation. Questions arise regarding the correct application of the gamma factor and how to relate the crew's time to the observer's time on Earth.

Discussion Status

There is ongoing exploration of the problem with various attempts to calculate the required velocity. Some participants have provided hints and guidance regarding the use of the gamma factor and the relationship between the time experienced by the crew and the time observed from Earth. However, there is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are grappling with the definitions and implications of time dilation and length contraction, as well as the correct application of the velocity formula. There is also uncertainty regarding the interpretation of the problem's requirements and the calculations involved.

spXq
Messages
4
Reaction score
0
The distance to Alpha Centauri is 4,3 light years. How fast would a spaceship have to travel to get there in 10 years, according to the crew?

The answer *should* be 0,395c. So far I've gotten all sorts of answers but not much close, so I seem to be approaching the problem the wrong way.
 
Physics news on Phys.org
Show what you've done so far.

Hints: What's the basic idea of time dilation? What's the definition of velocity?
 
The first part of the assignment asks for the time required when traveling at 30% of light speed. Given a gamma factor of 1,048 I get ~13,7 years, which is correct (so the gamma factor must be correct as well).

velocity = distance / time

But...

for t = 10 and d = 4,3

v = 4,3 / 10
v = 0,43, which is wrong

taking length contraction into account gives

4,3/1,048 = 4,1

v = 4,1 / 10
v = 0,41, which is still wrong
 
spXq said:
Edit: velocity = distance / time
Good. Keep going.

From Earth's viewpoint, you have the distance. What's the time?
 
Doc Al said:
Good. Keep going.

From Earth's viewpoint, you have the distance. What's the time?

Hmm... i don't know. :/

The distance is 4,3 ly but I don't know the speed, so how do I find the time?
 
Hang on... the time for the crew is 10 years so the time for the observer is t/gamma

10/1,048 = 9,54 years

Edit: no that's not right... I have no idea what I'm doing

Edit2: the time from Earth's viewpoint is d * gamma = 4,3 * 1,048 = 10,48 years, while the time is 10 years for the crew
 
spXq said:
Hang on... the time for the crew is 10 years so the time for the observer is t/gamma
You have that reversed. If the ship time is 10 years, then to Earth observers it will be longer: t*gamma, not t/gamma.

10/1,048 = 9,54 years
In addition to what I already pointed out, do not use the gamma from the previous part of the question.

So continue with that velocity equation, v = d/tearth.
 

Similar threads

Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 65 ·
3
Replies
65
Views
13K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K