How Fast Should a Space Station Rotate to Mimic Earth's Gravity?

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Homework Help Overview

The discussion revolves around calculating the angular speed required for a rotating space station to simulate Earth's gravity for its occupants. The space station's living quarters are designed in a circular ring with a diameter of 62.0 m.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between centripetal force and gravitational force, attempting to equate them to find the necessary angular speed. There are questions regarding the accuracy of calculations and the values used for gravitational acceleration.

Discussion Status

Some participants have provided feedback on the calculations, suggesting that the issue may stem from a misunderstanding of the diameter versus radius in the problem setup. There is an acknowledgment of the need for careful reading of the problem statement.

Contextual Notes

Participants note the importance of using the correct value for gravitational acceleration and the distinction between diameter and radius in the calculations.

Becca93
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Homework Statement
A proposed space station includes living quarters in a circular ring 62.0 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth?


The attempt at a solution

I assumed that to do this problem, Fcp had to equal the force of gravity.

Fcp = Fg

mv^2 / r = mg
v^2 / r = g
v = √(rg)
v = √(62g)
v = 24.65

v = ωr
ω = v/r
ω = 24.65 / 62
ω = 0.398 rad/s

This isn't correct.

Does anyone have any advice on what to do differently? Any help would be greatly appreciated.
 
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Becca93 said:
Homework Statement
A proposed space station includes living quarters in a circular ring 62.0 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth?


The attempt at a solution

I assumed that to do this problem, Fcp had to equal the force of gravity.

Fcp = Fg

mv^2 / r = mg
v^2 / r = g
v = √(rg)
v = √(62g)
v = 24.65

v = ωr
ω = v/r
ω = 24.65 / 62
ω = 0.398 rad/s

This isn't correct.

Does anyone have any advice on what to do differently? Any help would be greatly appreciated.

I don't see anything wrong with your physics. The problem may lie with your math. What value of g did you use? Using g = 9.81 N/kg, I get v = 24.66 m/s (to two decimal places).
 
cepheid said:
I don't see anything wrong with your physics. The problem may lie with your math. What value of g did you use? Using g = 9.81 N/kg, I get v = 24.66 m/s (to two decimal places).

I tried both, but when whittled down to the required three sigfigs, the answer is still 0.398 rad/s.

I'm at a loss as to what to do differently.
 
Becca93 said:
I tried both, but when whittled down to the required three sigfigs, the answer is still 0.398 rad/s.

I'm at a loss as to what to do differently.

Oh. :redface:

62.0 m is the diameter of the space station, not its radius.

It helps if you read the problem carefully (and I apply this advice to you and me both!).
 
cepheid said:
Oh. :redface:

62.0 m is the diameter of the space station, not its radius.

It helps if you read the problem carefully (and I apply this advice to you and me both!).

:redface: Do you ever have one of those moments where you just can't believe you mixed up something really simple?

Thank you very much for pointing that out. I feel a bit foolish, but I do have the right answer now.
 

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