How Fast Was the Car from City B Initially?

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Homework Help Overview

The problem involves two cars departing from different cities and meeting at a certain distance apart, with the goal of determining the speed of the car that initially leaves from city B. The cars are said to have constant acceleration and meet a second time after a specified duration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to break down the problem into equations related to the cars' movements and meetings, expressing uncertainty about the number of equations needed. Some participants suggest conceptualizing the problem and minimizing the number of equations and unknowns. Others discuss the implications of the distance and time constraints on the solutions.

Discussion Status

Participants are actively engaging with the problem, questioning the original poster's approach and the number of equations used. There is recognition of multiple interpretations and potential solutions regarding the distance and speeds of the cars, though no consensus has been reached on a specific method or solution.

Contextual Notes

There are indications of ambiguity in the problem statement, and participants note the importance of understanding the constraints on the distance and time involved in the cars' journeys.

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Homework Statement


Two cars leave at the same time (one from city A and the other from city B) and drive toward each other. They first meet d=45 km far from B . Both cars reach their destination (B for the former, A for the latter) and then start driving to their initial cities.The cars have constant acceleration. They meet a second time after t=3 hours from their first meeting. What is the speed of the vehicle which (initially) leaves from B?

Homework Equations


x=vt

The Attempt at a Solution


I tried fragmenting the problem. First I wrote the equations for the first meeting of the cars (d=vB*t0, D-d=vA*t0, where D is the distance between A and B) then the equations for the arrival of car B (the one which leaves from B) while car A has not yet arrived (I considered B to be faster). Then the equations for the arrival of car A and finally, the equations for the second meeting. I got 9 equations including the one for the time and I am not sure this is the right way to solve the problem. I also thought about considering the cars to be moving in a circle,but couldn't get enough equations.

I am sorry for any translation mistakes. I, myself, have found the original problem statement to be ambiguous, but I tried to translate it as accurate as possible.
 
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If you have not already done so, can you derive the equation

##Dv_b = 45(v_a + v_b)##

where ##D## is the distance between the cities.
 
Last edited:
well.. 9 equations? that's a lot...
what equations and unknowns did you get?
You need to conceptualize the problem, draw out the important moments ofthe problem and do the minimum equations and the minimum unknowns possible.
start by writing out the equations for the stated moments(first meet, reach city, second meet, reach city)
this has multiple possible answers!
 
WrongMan said:
well.. 9 equations? that's a lot...
what equations and unknowns did you get?
You need to conceptualize the problem, draw out the important moments ofthe problem and do the minimum equations and the minimum unknowns possible.
start by writing out the equations for the stated moments(first meet, reach city, second meet, reach city)
this has multiple possible answers!
There's only one answer for ##v_b##.
 
PeroK said:
There's only one answer for ##v_b##.
oh right my mistake
 
WrongMan said:
oh right my mistake
There are multiple solutions for ##D## and ##v_a##, though.
 
PeroK said:
There are multiple solutions for ##D## and ##v_a##, though.
ah yes... not crazy after all... its just when i see these kind of problems i have to find all unknowns and forget i was only supposed to find one... and i don't allways write everything on paper...
now that i think (more) about it D can't change that much... carB has to get to A in at least 3 hours, right?
 
Yes, there must be upper and lower limits on ##D##.
 
PeroK said:
If you have not already done so, can you derive the equation

##Dv_b = 45(v_a + v_b)##

where ##D## is the distance between the cities.
Can you please tell me more about this equation? I have just started using derivatives in physics and I'm having trouble understanding where this equation came from and what it means. Is D a function? If so, I think the result would be 45.
 
  • #10
PITPin said:
Can you please tell me more about this equation? I have just started using derivatives in physics and I'm having trouble understanding where this equation came from and what it means. Is D a function? If so, I think the result would be 45.
As I said, ##D## is just the distance between the cities. I was using your notation from post #1!
 

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