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How get amplitude and phase as a function of time?

  1. May 1, 2014 #1
    Given a function of the time like ##f(t)##, its Fourier transform is ##F(\nu)## and by definition, ##Abs(F(\nu))=A(\nu)## and ##Arg(F(\nu)) = \varphi(\nu)##, so I have amplitude and phase as function of the frequency, but make sense speak in amplitude and phase as function of the time? If yes? How get them?
     
  2. jcsd
  3. May 1, 2014 #2
    [itex]\text{abs}(f(t))[/itex] and [itex]\text{arg}(f(t))[/itex] of course
     
  4. May 1, 2014 #3
    But if f(t) = cos(t) thus the amplitude as function of the time is A(t) = 1 and the phase is φ(t) = 0 what is different of Abs(f(t)) and Arg(f(t)), respectively.
     
  5. May 1, 2014 #4
  6. May 2, 2014 #5
    argument is different of phase
     
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