How High and Far Does a Soccer Ball Travel When Kicked?

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Homework Help Overview

The discussion revolves around the physics of projectile motion, specifically analyzing the trajectory of a soccer ball kicked into the air. The original poster presents a scenario involving the ball's height, velocity, and the calculations needed to determine its maximum height, horizontal distance traveled, and impact velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply kinematic equations to find the maximum height and range of the soccer ball but expresses uncertainty about the necessary variables. Participants question the vertical velocity at maximum height and the time it takes to reach that point. There is also discussion about the calculations for the final velocity upon impact and the use of the Pythagorean theorem.

Discussion Status

Some participants have provided guidance on the calculations, confirming the correctness of certain values while noting discrepancies in the final vertical velocity. There is an ongoing exploration of the steps involved in reaching the correct answer, with no explicit consensus on the final outcome yet.

Contextual Notes

Participants are working under the assumption of neglecting air resistance and are navigating through the complexities of projectile motion equations. There is mention of potential errors in calculations and the need for clarification on specific variables.

Psyguy22
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Neglect air resistance for the following. A soccer ball is kicked from the ground into the air. When the ball is at a height of 10.07 m, its velocity is (vx,vy) = (4.63,3.83) m/s.
To what maximum height will the ball rise?
What horizontal distance will be traveled by the ball?
With what velocity (magnitude and direction) will it hit the ground?

I haven't started the second and third question yet. I wanted to use the equation y=1/2gt^2+Viy*t but I don't know what time or y is. Then I tried y=yo+tan(θ)x+g/(2v^2*cos(θ)^2)*x^2, but I don't have enough info to use it. Would I be wrong to move 10.07 to the origin, then use 0=1/2gt^2 to find maximum height?
 
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What the ball reaches its max height, what is its vertical velocity? How much time will that take from any known value of the vertical velocity?
 
dory, I was braindead last night. I figured out that the max height is 10.82 m and the range is 13.75 m. although the last one is still bothering me.
I found the time it took the ball to hit the ground from height=10.82 which was about 1.47 s. I used 1.47 in Vy=gt (because Vy at max height is 0) and came up with -7.355 m/s. so I used Pythagorean theorem to find the velocity when it hits the ground. I came up with 8.69 m/s and used atan(-7.355/4.63) to get -57.81 deg. But the site says its wrong. I don't know which number Is wrong or if I did a step wrong.
 
sorry*
guess I still am -_-
 
The max height and range you got are correct. The time from the max height to the ground is correct, too. However, the final vertical velocity is wrong. Calculate it again from the formula you have.
 
ohh.. I have bad handwritind -_- thank you. I did get the right answers
 

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