- #1
Psyguy22
- 62
- 0
Neglect air resistance for the following. A soccer ball is kicked from the ground into the air. When the ball is at a height of 10.07 m, its velocity is (vx,vy) = (4.63,3.83) m/s.
To what maximum height will the ball rise?
What horizontal distance will be traveled by the ball?
With what velocity (magnitude and direction) will it hit the ground?
I haven't started the second and third question yet. I wanted to use the equation y=1/2gt^2+Viy*t but I don't know what time or y is. Then I tried y=yo+tan(θ)x+g/(2v^2*cos(θ)^2)*x^2, but I don't have enough info to use it. Would I be wrong to move 10.07 to the origin, then use 0=1/2gt^2 to find maximum height?
To what maximum height will the ball rise?
What horizontal distance will be traveled by the ball?
With what velocity (magnitude and direction) will it hit the ground?
I haven't started the second and third question yet. I wanted to use the equation y=1/2gt^2+Viy*t but I don't know what time or y is. Then I tried y=yo+tan(θ)x+g/(2v^2*cos(θ)^2)*x^2, but I don't have enough info to use it. Would I be wrong to move 10.07 to the origin, then use 0=1/2gt^2 to find maximum height?