How high is the snow pile if a kid jumps off it and lands on the ground?

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SUMMARY

The discussion centers on calculating the height of a snow pile based on a kid's jump, using the equation of motion S = v0t + (at^2)/2. The participant concluded that the total time of ascent and descent is 0.8 seconds, leading to a calculated height of -0.8144 meters, indicating an error in the assumptions. The key mistake identified was the incorrect treatment of velocity and acceleration signs, particularly regarding gravitational acceleration (g), which should be negative when considering downward motion.

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinematics.
  • Familiarity with the equation of motion S = v0t + (at^2)/2.
  • Knowledge of gravitational acceleration, specifically g = 9.81 m/s².
  • Ability to interpret velocity vs. time graphs.
NEXT STEPS
  • Review kinematic equations and their applications in projectile motion.
  • Study the concept of velocity and acceleration signs in physics problems.
  • Practice solving problems involving free fall and jumps using real-world scenarios.
  • Explore graphical representations of motion, focusing on velocity vs. time graphs.
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Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics in real-world contexts.

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Homework Statement


The diagram shows a kid jumping off a snow pile into the grown that is also covered with snow. So the kid is jumping up and then lands on the ground.
https://scontent-arn2-1.xx.fbcdn.net/hphotos-xpf1/v/t34.0-12/12380374_1234806623215387_1066477107_n.jpg?oh=fe84392440a1ddbf0eebf557109d56ec&oe=5677CAA8
The question is: how tall is the snow pile if the ground is 0 m?

Homework Equations



S=v0t + (at^2)/2

The Attempt at a Solution


I am thinking that the kid is at its highest point when the velocity is zero and t=0.4. It takes 0.4 seconds up and also 0.4 seconds down to the level where the snow pile was at. so the snow piles height is from 0.8 seconds to 1,2 seconds. 1.2-0.8=0.4
s= -4*0.4 + (9.82 * 0,4^2)/2 = - 0,8144

What went wrong in my assumptions or solution?

upload_2015-12-19_14-42-36.png
 
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If it's headed downwards, you are denoting this as a negative velocity, so g in your equation will likewise be negative.
 
Also, when the velocity is at its most negative point, that's when the kid reaches the top of the layer of snow that's on the ground, not the ground itself. Ponder the finish of the velocity vs time graph.
 

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