2 Billion People Jumping Off Ladders Simultaneously

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Homework Help Overview

The problem involves a scenario where 2 billion people, each with an average mass of 50 kg, jump off 1-meter tall ladders simultaneously, resulting in an inelastic collision with the Earth. The discussion centers around the implications of this collision, particularly regarding the initial velocities of the individuals and the resulting effects on the Earth.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the initial velocity of the individuals before jumping, questioning whether it should be considered as 0 or as their speed just before impact. There is also discussion about the conservation of momentum in the context of an inelastic collision and the implications for the Earth's velocity post-collision.

Discussion Status

Participants have raised various questions about the initial conditions and the nature of the collision. Some guidance has been provided regarding the use of conservation of momentum, and there is acknowledgment of the center of mass remaining unchanged during the event. Multiple interpretations of the problem are being explored without a clear consensus.

Contextual Notes

There is a specific focus on the scenario being limited to individuals in China, and participants are considering the implications of this setup on the overall analysis of the collision.

Idioticsmartie
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Homework Statement


Let us say there are 2 billion people with an average mass of 50 kg. They all climb ladders which are 1 meter tall. At a particular instant they all jump off nd land on the ground simultaneously. This is an inelastic collision with the Earth. Assume the Earth does not move prior to the collision


Homework Equations


0.5m_{a}v^{2}_{a} + 0.5m_{b}v^{2}_{b} = 0.5m_{a}v^{'2}_{a} + 0.5m_{b}v^{'2}_{b}

v^{2} = v^{2}_{0} + 2a(x-x_{0})

The Attempt at a Solution


I think I can solve this, I'm just confused about whether or not the initial velocity for the people is 0 (before they all jump) or if it's 4.29 m/s (their speed just before they collide with the earth)

Or would it work either way?
 
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Are you supposed to find the velocity of the Earth after the collision?

It's an inelastic collision... so you can't use conservation of kinetic energy.
You need to use conservation of momentum...

Find the velocity with which the people hit the ground... then use conservation of momentum.
 
so the initial velocity of the people is 0, before they jump, right?
 
Idioticsmartie said:
so the initial velocity of the people is 0, before they jump, right?
Sure.

What are you supposed to figure out? Are the people evenly spaced around the earth?
 
No, they're all in China. So I just need to find the velocity of the Earth afterwards. And figure out realistically if the center of mass changes during the collision, which it doesn't, because the Earth accelerates towards the people, doesn't it?
 
That's right. Since there are no external forces, the center of mass of Earth + people doesn't change no matter what they do.

Do as learningphysics suggested.
 
Great - thanks!
 
Wait, sorry - is the velocity prime (aka after the collision) the same for both people and earth, since they become one object?
 
Idioticsmartie said:
Wait, sorry - is the velocity prime (aka after the collision) the same for both people and earth, since they become one object?

Yes... if it is given that the people don't bounce back up from the earth.
 

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