How Is Air Pressure Calculated in a Crushed Can Experiment?

  • Thread starter Thread starter bleedblue1234
  • Start date Start date
  • Tags Tags
    Fluids
Click For Summary
SUMMARY

The discussion focuses on calculating the total force exerted by air pressure on a rectangular metal can during a physics demonstration. The can's dimensions are 0.234 meters by 0.194 meters by 0.143 meters, and the calculation involves determining the surface area of the can and applying the air pressure of 101300 Pa. The final force calculated is 21594.16 N, confirming the effectiveness of the method used to demonstrate the crushing effect of air pressure when the can is cooled after boiling water.

PREREQUISITES
  • Understanding of basic physics concepts, specifically pressure and force.
  • Familiarity with the formula for calculating area of rectangular surfaces.
  • Knowledge of atmospheric pressure, specifically 1 atm = 101300 Pa.
  • Ability to perform unit conversions and calculations involving Newtons (N).
NEXT STEPS
  • Research the principles of atmospheric pressure and its effects on objects.
  • Explore the concept of vacuum and its applications in physics experiments.
  • Learn about the relationship between pressure, volume, and temperature in gases (Ideal Gas Law).
  • Investigate other experiments demonstrating air pressure effects, such as the "crushed can" experiment variations.
USEFUL FOR

This discussion is beneficial for physics students, educators conducting demonstrations, and anyone interested in understanding the principles of air pressure and its practical applications in experiments.

bleedblue1234
Messages
108
Reaction score
0

Homework Statement



A rectangular metal can with dimensions of 0.234 meters by 0.194 meters by 0.143 meters is used in a physics demonstration to show the force exerted by air pressure. A small quantity of water is poured into the can and brought to a boil. Then the can is capped and allowed to cool, which crushes the can. What is the total force exerted on the can by the air around it, assuming a perfect vacuum inside?

Homework Equations



1 atm = 101300 Pa

The Attempt at a Solution



so just find the area of each of the three sides and multiply by 2

so 2(.234*.194)+2(.194*.143)+2(.234*.143)
and so i got .2132 m^2

so then we know

101300 Pa = N/m^2

so 101300pa * .2132 m^2 = N

so N = 21594.16

am i right?
 
Physics news on Phys.org
Looks good!
 

Similar threads

  • · Replies 23 ·
Replies
23
Views
2K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K