The calculation of angular speed for a pulley system involves the relationship between linear velocity and angular velocity, expressed as v = rω. In the context of the discussion, the angular speed (ω) can be derived using the formula ω = (1/R) * √((2gh)(mA - mB) / (mA + mB + I/R²)), where R is the radius of the pulley, g is the acceleration due to gravity, h is the height, and mA and mB are the masses of the boxes. The conservation of energy principle is also applicable in this scenario, confirming the correctness of the approach taken by the participants.
PREREQUISITESPhysics students, mechanical engineers, and anyone studying dynamics and energy conservation in mechanical systems will benefit from this discussion.
That all looks right.dennislam said:Homework Statement
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Homework Equations
v=rω
conservation of energy
The Attempt at a Solution
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I don't know whether it is correct or not, and I am quite confused in part b
it asks the angular speed of the pulley
can I say that v=rω since the pulley and box A,B have a common velocity?
so is ω equal to 1/R*√((2gh)(mA-mB)/(mA+mB+I/R^2))?
but the question is worth 10 marks