1. The problem statement, all variables and given/known data A counterweight of mass m 5 4.00 kg is attached to a light cord that is wound around a pulley. The pulley is a thin hoop of radius R = 8.00 cm and mass M = 2.00 kg. The spokes have negligible mass. When the counterweight has a speed v, the pulley has an angular speed v = v/R. Determine the magnitude of the total angular momentum of the system about the axle of the pulley 2. Relevant equations 3. The attempt at a solution I know the answer is L = rmv = (0.08)(2 + 4)v = 0.48v but i don't understand why you have to add the momentum of the block using the equation of angular momentum I mean, it is not moving in a circle, it is moving in a straight line downward. My original calculation was L = (0..08)(2)(v) + (4)(v) Is this because when the block "transfers" its momentum to the pulley, its momentum will "act on" the surface of pulley at 0.08 m which is why I have to calculate it like (4)(v)(0.08)? Thanks!