- #1

thatstheguy9

- 14

- 3

- Homework Statement:
- Determine the angular velocity of Pulley B and C

- Relevant Equations:
- ## V = \omega r ##

So far I have:

The velocity of the belt will be the same for pully A and D, so we can calculate the angular velocity of pulley D:

## V_A = V_B ##

## \omega_A r_A = \omega_D r_D ##

## ((20*3)+40)(0.075) = \omega_D (0.025) ##

## \omega_D = 300 Rad/s ##

My next step was to determine the angular velocity of pulley B. My thought was because pully B and pulley D are joined on the same shaft they must have the same velocity.

I determined ## \omega_B = 75 Rad/s ##.

However the solution found ## \omega_B = 300 Rad/s ##.

I don't understand how the larger pulley can have a higher velocity than the smaller pulley. Or why the velocity of pulley A is the same as pulley B. Can someone explain this?

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