How Is Central Acceleration Calculated for Uniform Circular Motion?

[Ockonal]

Some point moves in a circle with V = const; V = 50 m/s. Speed vector changes it's direction 30⁰ per 2 seconds. Find central acceleration.
$$\omega = \frac{\varphi }{t}$$
$$\omega = \frac{30}{2} = 15 (\frac{rad}{sec})$$
$$\upsilon = \omega * R$$
$$50 = 15 * R; R = 3.33 (m)$$
$$a = \frac{\upsilon^2}{R}$$
$$a = \frac{50^2}{3.33} = 751 (m/s^2)$$

I'm not sure it's right.

 

[Doc Al]

$$\omega = \frac{30}{2} = 15 (\frac{rad}{sec})$$

The angle is given in degrees, not radians. Convert.

 

[Ockonal]

Okay, thanks. Not including this, all another part of my exercise is right?

 

[Doc Al]

Not including this, all another part of my exercise is right?

Yes, you've got the right idea.