How Is Force Calculated on Bicycle Pedals When Cycling Uphill?

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SUMMARY

The discussion focuses on calculating the force exerted on bicycle pedals when cycling uphill, specifically on a 7.00° incline with a vertical height of 122 m. The total work done against gravity is calculated using the formula (m)(g)(d), resulting in 91100 J for a cyclist and bicycle mass of 76.2 kg. To find the average force exerted on the pedals, the distance moved per pedal revolution (5.00 m) is used, along with the pedal diameter of 34.6 cm, to derive the necessary force at the pedals through torque conversion. The analysis neglects friction and other losses for simplicity.

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force exerted on the pedals...?

-) A cyclist intends to cycle up a 7.00° hill whose vertical height is 122 m. Assuming the mass of bicycle plus person is 76.2 kg, calculate how much work must be done against gravity. I got this part by multipling the (m)(g)(d)= 91100
If each complete revolution of the pedals moves the bike 5.00 m along its path, calculate the average force that must be exerted on the pedals tangent to their circular path. Neglect work done by friction and other losses. The pedals turn in a circle of diameter 34.6 cm.
I really have no idea :confused: . so if u can help me with that
thanx
 
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Think about it. You know the required force at the wheels,.. and 1 rev of the pedel = 5 m,.. total path is known,... divide to get the amount of force at the wheels per 1 rev of the pedels,...next use torque conversion to get force at pedals,.. remember 5 m is the outer lever distance,.. so the pedel requires more force than at the wheels
 

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