How Is Frequency Calculated in the Stern-Gerlach Experiment?

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SUMMARY

The discussion focuses on calculating the energy difference and frequency of radiation in the Stern-Gerlach experiment involving silver atoms. The magnetic moment is defined as μ = e/me S, with |S| = ℏ/2 and a magnetic field strength of 1T. The energy for each beam is derived as U = μs·B, leading to the energy difference ΔE = ℏ(e/me) for g ≈ 2 and B = 1. The participant expresses confusion regarding the calculation of frequency for the radiation that induces transitions between these energy states.

PREREQUISITES
  • Understanding of quantum mechanics, specifically spin and magnetic moments
  • Familiarity with the Stern-Gerlach experiment and its principles
  • Knowledge of energy calculations in magnetic fields
  • Basic grasp of electromagnetic radiation and frequency calculations
NEXT STEPS
  • Research the relationship between energy difference and frequency using the formula E = hν
  • Study the concept of quantized energy levels in quantum mechanics
  • Explore the significance of the Bohr Magneton in magnetic moment calculations
  • Examine the role of the g-factor in determining energy states in magnetic fields
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying atomic physics and the Stern-Gerlach experiment, as well as educators looking to clarify concepts related to magnetic moments and energy transitions.

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Homework Statement



I have a Stern-Gerlach experiment with a beam of silver and a magnetic moment due to the spin of the single valence electron give by μ=e/me S. And |S|=ℏ/2. The magnetic field is 1T.

The problem asks to compute the energy difference of the silver atoms in the two existing beams. The second part - which I am really confused on - Next up I am to find the frequency of the radiation that would induce a transition between these two states.

Homework Equations




The Attempt at a Solution



The energy of each beam is U=μs·B

Hence the energy is

E=\pm \frac{1}{2} \hbar \frac{e}{m_e} g B

Therefore ΔE is

E= \frac{1}{2} \hbar \frac{e}{m_e} g B ~+~ \frac{1}{2} \hbar \frac{e}{m_e} g B~=~ \hbar \frac{e}{m_e}

Where g≈2 and B=1 so there is a little cancelling.

My units end up being N·m = J.

I am worried this is wrong. My answer is really close to the Bohr Magneton. It is off by a 2 in the denominator and my units aren't quite right. So I guess first off, did I proceed correctly so far?

If that is correct, how does one even begin the second half? With no quantized energies I don't know where to start.
 
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I'm assuming it involves the energy difference, but I'm not sure. Any help would be greatly appreciated!
 

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