How Is Friction Force Calculated in Physics Problems?

[hkin2019]

Homework Statement

Box Mass = 64.7 kg T1 = 22.5° T2 = 54.1° F = 2327.9 N

μdynamic = 0.19 μstatic = 0.37

What is the force of friction acting on the box?

Homework Equations

FF= mu x FN

The Attempt at a Solution

64.7 x 9.81 = 634.707
0.19 x 634.707 = 120.69

Computer is telling me that it is incorrect

 

[mfb]

You should work with units (maybe that’s the problem already?). For the dynamic friction I get 120.5[/color]9 N - assuming the box is on a horizontal surface. There are other things given, it looks like the problem is more than that single question.

 

[kuruman]

What kind of angles are T1 and T2? What is F? What is the complete statement of the problem?

 

[hkin2019]

T1= 22.5
T2=54.1
F=2327.9N

The statement is finding the force of friction on a box on a slope in the horizontal direction

 

[mfb]

What are T1 and T2? Not their values, but what is their meaning?

Is there a sketch of the setup?

 

[hkin2019]

What are T1 and T2? Not their values, but what is their meaning?

Is there a sketch of the setup?

 

[hkin2019]

T1 & T2 are angles T1 is the angle of the slope at the bottom
and T2 is the angle off of the box where F is coming off of

 

[mfb]

Which slope?
We don't have a crystal ball. If you don't show the full problem statement, it is impossible to help.

I guess the problem came with a sketch. Please share this sketch.