How is Gravitational Potential Calculated on the Moon's Surface?

  • Thread starter Thread starter Pho3nix
  • Start date Start date
  • Tags Tags
    Gravitation
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 3K views
Pho3nix
Messages
4
Reaction score
0
[SOLVED] Gravitation Problem

Homework Statement


The moon has a mass of 7.7times10^22kg and radius 1.7times10^6m. Calculate:
a) The gravitational potential at its surface.
b) The work needed to completely remove a 1.5times10^3kg spacecraft from its surface into outer space.
c) What is the minimum speed which a body must have to escape from the moons gravitational field?

Homework Equations


Vg=-GM/r
Ep=GMm/r
Ek=.5m(vsquared)
Vg is the gravitational potential
Ep is potential energy


The Attempt at a Solution


a) Vg=GM/r
G=6.67times10^-11
M=7.7times10^22kg
r=1.7times10^6m
Plug in the numbers and I get -3.0times10^6
b)Ep=Gmm/r
M=7.7times10^22Kg
m=1.5times10^3Kg
r=1.7times10^6
Plug in numbers and get -4.5times10^9 Joules
c)In need help on this one.
 
Physics news on Phys.org
Pho3nix said:
c)In need help on this one.

Equate the KE to the work done in (b). That gives you the minimum v, which is called the escape velocity, which is the minimum speed that has to be given to the body remove it to infinite distance.