How Is Jordan Normal Form Useful for Physicists?

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Jordan normal form is valuable for physicists as it allows for the "almost" diagonalization of non-diagonalizable matrices, facilitating the extraction of eigenvalues and eigenvectors. The eigenvalues are easily identifiable along the diagonal, and each Jordan block corresponds to a single eigenvector, simplifying analysis. Understanding eigenvalues is crucial for computing matrix functions, particularly in solving linear systems of differential equations. The Jordan form enables explicit calculation of the matrix exponential, which is essential in various physics applications. Overall, it provides a systematic approach to handle complex matrices encountered in physical problems.
fluidistic
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Hi guys,
This isn't a homework question but it's course related. In my mathematical methods in Physics course we were introduced the Jordan normal form of a matrix.
I didn't grasp all. What I understood is that when a matrix isn't diagonalizable, it's still possible (only sometimes; depending on the given matrix), to "almost" diagonalize it.
I'd like to know what is the point of doing so, especially how can it be used for physicists and in what kind of problems such matrices can appear.
Thanks a lot!
 
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The main reason it helps is because you can read the eigenvectors and eigenvalues off very easily. The eigenvalues are along the diagonal. Each Jordan block yields only one eigenvector which is the column vector of the form (1, 0, 0...)^{T} so you can organize your matrix into many Jordan Blocks and you have your eigenvectors too.

Maybe there are more uses but this is what strikes me as most significant.
 
McLaren Rulez said:
The main reason it helps is because you can read the eigenvectors and eigenvalues off very easily. The eigenvalues are along the diagonal. Each Jordan block yields only one eigenvector which is the column vector of the form (1, 0, 0...)^{T} so you can organize your matrix into many Jordan Blocks and you have your eigenvectors too.

Maybe there are more uses but this is what strikes me as most significant.

Thanks. I knew this but why would knowing eigenvalues be important if the matrix isn't even diagonalizable?
 
fluidistic said:
Hi guys,
This isn't a homework question but it's course related. In my mathematical methods in Physics course we were introduced the Jordan normal form of a matrix.
I didn't grasp all. What I understood is that when a matrix isn't diagonalizable, it's still possible (only sometimes; depending on the given matrix), to "almost" diagonalize it.
I'd like to know what is the point of doing so, especially how can it be used for physicists and in what kind of problems such matrices can appear.
Thanks a lot!

You need it in computing functions of the matrix. For example, one way to solve a linear system of constant-coefficient DEs of the form dX/dt = A*x is to write X(t) = X_0*exp(A*t), so you need the exponential of a matrix. Knowing the Jordan normal form allows you to write down the matrix exponential explicitly.

RGV
 

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