How is Kinetic Energy Conserved in an Elastic Collision?

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SUMMARY

The discussion focuses on the conservation of kinetic energy in elastic collisions, specifically involving two steel balls with masses of 8.5 kg and 5 kg. The total kinetic energy before the collision is calculated to be 612 Joules using the formula 1/2mvi2. To solve for the velocities of both balls after the collision, participants emphasize the necessity of applying both conservation of momentum and conservation of kinetic energy principles.

PREREQUISITES
  • Understanding of elastic collisions
  • Familiarity with the conservation of momentum
  • Knowledge of kinetic energy calculations
  • Proficiency in algebraic manipulation of equations
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  • Study the principles of elastic collisions in detail
  • Learn how to apply conservation of momentum in collision problems
  • Explore kinetic energy formulas and their applications in physics
  • Practice solving problems involving multiple objects in collisions
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of kinetic energy conservation.

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Homework Statement


A 8.5 kg steel ball, traveling left to right at 12 m/s, undergoes an elastic collision with a 5 kg steel ball at rest. To the nearest Joule, what is the Total Kinetic Energy of the two balls after collision? If the first ball has a mass of 10 kg and the second ball is traveling at it with a speed of 3 m/s, what is the velocity, to one decimal place, of the first ball after collision? What is the velocity of the second ball to one decimal place?

Homework Equations



1/2mvi2+1/2mvii2=KE

The Attempt at a Solution


Question 1:
1/2 (8.5)(122)= 612 J
Question 2 & 3:
I'm not sure the equation needed to solve for the needed. I'm pretty sure that if I can get question 2 then the same method will be used to solve question 3.
 
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For questions 2 and 3 you need to conserve momentum in addition to energy conservation.
 

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