How Is Mechanical Energy Calculated in Thrown Objects?

[new^2^physics]

1. Homework Statement

A 0.50 kg rubber ball is thrown into the air. At a height of 20 m above the ground, it is traveling at 15 m/s.
a. what is the balls kinetic energy
b. What is its gravitational potential energy relative to the ground?
c. how much work was done by someone at ground level throwing the ball into the air?
d. What was the speed of the ball when it left the ground?3. The Attempt at a Solution

a. Ek = 1/2 mv2
Ek = 1/2 (0.50kg)(15m/s)
Ek = 1/2 (0.50 kg)(225 m2/s2)
Ek = 1/2 (112.5 J)
Ek = 56 J

b. Eg = mgh
Eg = (0.50kg)(9.80 N/kg)(20m)
Eg = 98 J

c. W = fd
ANSWER = 150
HELP ME PLEASE

d. PLEASE HELP!

 

[rock.freak667]

For part C, the law of conservation of mechanical energy would say that KE+PE=constant. So the person would need to supply that much energy.