How Is Kinetic Energy Calculated at the Peak of a Baseball's Trajectory?

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Homework Help Overview

The discussion revolves around calculating the kinetic energy of a baseball at the peak of its trajectory, focusing on the effects of initial speed and angle of projection. The subject area is kinematics, particularly the conservation of energy in projectile motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate kinetic energy using the initial speed and angle, questioning whether to apply conservation of energy principles instead. Participants discuss the importance of considering velocity components and the implications of vertical and horizontal motion at the peak.

Discussion Status

Participants are exploring the relationship between vertical and horizontal components of velocity at the peak of the trajectory. Some guidance has been offered regarding the use of trigonometric functions to resolve velocity components, and there is acknowledgment of the vertical velocity being zero at the highest point.

Contextual Notes

The original poster's calculations and assumptions are under scrutiny, particularly regarding the use of sine and cosine functions for velocity components. There is a focus on the implications of energy conservation in the context of projectile motion.

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Homework Statement


an outfielder throws a 2.15 kg baseball at a speed of 113 m/s and an initial angle of 11.2 degrees. What is the kinetic energy of the ball at the highest point of its motion.


Homework Equations


KE = 1/2mv^2

KE(initial) + PE(initial) = KE (final) + PE (final)


The Attempt at a Solution



KE = 1/2 (2.15 kg) (113* sin 11.2)^2
KE =517.866

My method seems too simple. Should I be using the conservation of energy equation and if so, how should I go about doing it?
 
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Almost right - have a look at you sine/cosine.

You know that you can consider the velocity components in the horizontal and vertical directions independently. What are the forces acting along each direction of the velocity components? When the ball is at its highest point, what can you say about the ball's vertical velocity? And what about the horizontal velocity?

As I say, you've almost got it right, just look at splitting the velocity into components again. :smile:
 
when the ball is at its highest point, the ball's vertical velocity would be zero? Should I have used: KE = 1/2 (2.15 kg) (113* cos 11.2)^2 instead?
 
That is correct.
 

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