How Is Momentum Calculated for a Decomposing Particle in Relativistic Physics?

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SUMMARY

The discussion focuses on calculating the momentum of a particle with mass Q resulting from the decomposition of a mass M particle at rest, which also produces a massless particle. The relevant equation is derived from the conservation of energy and momentum, specifically using the equation E^2_{cm}=m^2c^4=(\sum{E})^2-(\sum{P})^2c^2. The final momentum of the Q particle is expressed as p2 = Q*g*v, where v is determined by the relationship v/c = (M^2-Q^2)/(M^2+Q^2). This analysis emphasizes the importance of understanding relativistic momentum and energy conservation in the center of mass frame.

PREREQUISITES
  • Understanding of relativistic momentum and energy conservation
  • Familiarity with the center of mass frame in physics
  • Knowledge of the equation E^2_{cm}=m^2c^4=(\sum{E})^2-(\sum{P})^2c^2
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the principles of relativistic energy-momentum relationships
  • Learn about the center of mass frame in relativistic collisions
  • Explore the implications of massless particles in relativistic physics
  • Practice solving problems involving conservation of momentum and energy in particle decay scenarios
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying relativistic mechanics, as well as educators and researchers interested in particle physics and energy conservation principles.

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[SOLVED] relativistic momentum

Homework Statement


a particle with mass M and v=0 decomposes to a massless particle and another particle with the mass Q.
find the momentum of the Q particle

Homework Equations


[tex]E^2_{cm}=m^2c^4=(\sum{E})^2-(\sum{P})^2c^2[/tex]


The Attempt at a Solution


i tried using that equation and also tried to do some equations with the conservation of energy and momentum but i just can't figure it out
please help if you can
thanks
and also if you can explain to me the whole deal with center of mass in relativistic momentum and energy
when does the conservation of energy apply?
what happens in the center of the mass as oppose of out of it?
 
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Energy and momentum are always both conserved. So the total momentum after the decay is zero. So the momentum of Q is equal in magnitude to the momentum of the massless particle. Now apply conservation of energy. And apply m^2*c^4=E^2-P^2*c^2 to each particle. You should basically get two equations in two unknowns.
 
Suppose p1 is the momentum of the massless particle to the left and p2 is the mom of the particle with rest-mass Q to the right, with speed v. Let g denote gamma(v).

p1=p2=Qgv => Also, from energy consvn,

p1c + Qgc^2 = Mc^2 => (cancel c)
Qgv + Qgc = Mc. From this, the value of v comes out in terms of M, Q and c. Not difficult if you factorize and use compodendo-dividendo. Do the algebra. We get,

v/c = (M^2-Q^2)/(M^2+Q^2). Then,

p2 = Q*g*v, all expressed in terms of M, Q and c.
 

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