How is my integration wrong? X(

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My set-up for the integral is right:

2[itex]\pi[/itex]∫0 to 4 of (x)(√(4x) - (2x - 4))dx

= 2[itex]\pi[/itex]∫(2x3/2 - 2x2 + 4)dx

When I Wolfram Alpha the answer, it is 448[itex]\pi[/itex]/15.
The computer HW system counts that answer as correct.

But when I try to take the integral, it's wrong! :(

I did this...:

2[itex]\pi[/itex](2x5/2/5/2 - 2(x3)/3 + 4x2/4] |0 to 4

= 29.86[itex]\pi[/itex]

...This is not right. But what's the matter with my integration?

Thanks SO much for the help! :)
 
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Lo.Lee.Ta. said:
My set-up for the integral is right:

2[itex]\pi[/itex]∫0 to 4 of (x)(√(4x) - (2x - 4))dx

= 2[itex]\pi[/itex]∫(2x3/2 - 2x2 + 4)dx

When I Wolfram Alpha the answer, it is 448[itex]\pi[/itex]/15.
The computer HW system counts that answer as correct.

But when I try to take the integral, it's wrong! :(

I did this...:

2[itex]\pi[/itex](2x5/2/5/2 - 2(x3)/3 + 4x2/4] |0 to 4

= 29.86[itex]\pi[/itex]

...This is not right. But what's the matter with my integration?

Thanks SO much for the help! :)

Where did 4x^2/4 come from?
 
Oh, sorry. I wrote down (4x^2)/2 on my paper but typed it wrong!

I meant (4x^2)/2
 
Lo.Lee.Ta. said:
My set-up for the integral is right:

2[itex]\pi[/itex]∫0 to 4 of (x)(√(4x) - (2x - 4))dx

= 2[itex]\pi[/itex]∫(2x3/2 - 2x2 + 4)dx

When I Wolfram Alpha the answer, it is 448[itex]\pi[/itex]/15.
The computer HW system counts that answer as correct.

But when I try to take the integral, it's wrong! :(

I did this...:

2[itex]\pi[/itex](2x5/2/5/2 - 2(x3)/3 + 4x2/4] |0 to 4

= 29.86[itex]\pi[/itex]

...This is not right. But what's the matter with my integration?

Thanks SO much for the help! :)

448/15 = 29.8666666...

I'm guessing the system wants the exact answer, not a rounded off decimal.
 
Yeah, I guess it was the rounding thing! Man! :/

Thank you SO much for helping! Simple problem! UGH! =_=