How Is Rest Mass Defined in a Universe with No Absolute Rest?

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Rest mass, or invariant mass, is defined within any inertial reference frame where an object can be considered at rest, despite the absence of absolute rest in the universe. The relationship between energy, momentum, and mass is described by the equation E^2 = (pc)^2 + (mc^2)^2, which holds true across different reference frames. Even at absolute zero, an object cannot achieve "absolute rest" due to the inherent motion of its constituent particles, which affects its measured mass. The mass of an object, such as a hot potato, is influenced by the motion of its particles, demonstrating that temperature can impact rest mass. Understanding rest mass requires recognizing the dependence on the frame of reference and the relativistic equations that govern momentum and energy.
hanii
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hey guys ...i've got a doubt..
when there is no absolute rest in the universe...how is rest mass defined?
 
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hanii said:
hey guys ...i've got a doubt..
when there is no absolute rest in the universe...how is rest mass defined?
There's always a frame in which the body (or its center of mass) is at rest. Nothing 'absolute' needed.
 
You can also calculate the "rest mass" (more properly called "invariant mass") using the energy and momentum as measured in any inertial reference frame, by solving the following equation for m:

E^2 = (pc)^2 + (mc^2)^2

In different reference frames you measure different values for E and p, but they always give you the same value for m.
 
A non-accelerating object is always at rest with respect to itself.
 
Yes there is no absolute rest, because particles are all moving fast. Unless reach absolute zero which would break the second law of thermodynamics or the uncertainty principle. But discussing relativity, I think, we talk more generally about macroscopic objects in reference frames.
 
ZealScience said:
Yes there is no absolute rest, because particles are all moving fast. Unless reach absolute zero which would break the second law of thermodynamics or the uncertainty principle. But discussing relativity, I think, we talk more generally about macroscopic objects in reference frames.

"Absolute rest" in this context means being able to define whether an object is at rest without reference to anything external. Even if we could cool an object down to absolute zero, it wouldn't be at "absolute rest" in this sense.
 
Let me add that the motion of the particles that make up a macroscopic object actually does increase the (rest) mass of that object. This blew my mind as a beginning grad student. A hot potato weighs more than a cold potato (though not much more!).
 
bcrowell said:
"Absolute rest" in this context means being able to define whether an object is at rest without reference to anything external. Even if we could cool an object down to absolute zero, it wouldn't be at "absolute rest" in this sense.

Of course it depends on reference frames, but with temperature particles are moving fast! The mass of electron that measured by scientists is the mass of moving electrons. They are not interested in inertial mass of electrons.
 
ZealScience said:
Of course it depends on reference frames, but with temperature particles are moving fast! The mass of electron that measured by scientists is the mass of moving electrons. They are not interested in inertial mass of electrons.

Yes, but that has nothing to do with what people mean when they refer to "absolute rest" in the context of SR.
 
  • #10
Doc Al said:
There's always a frame in which the body (or its center of mass) is at rest. Nothing 'absolute' needed.

so...we should be at rest relative to the frame of reference in which the object is...to find the rest mass of that object
 
  • #11
how is this equation derived? could u please explain me..
 
  • #12
hanii said:
how is this equation derived?

Do you mean this one?

jtbell said:
E^2 = (pc)^2 + (mc^2)^2

Here's one way to derive it: start with the equations for relativistic momentum and energy:

p = \frac {mv}{\sqrt{1 - v^2/c^2}}

E = \frac {mc^2}{\sqrt{1 - v^2/c^2}}

Solve them together to eliminate v. For example, by solving one equation for v and substituting it into the other one.
 

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