How is rotation mathematically defined beyond the rotation matrix?

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Discussion Overview

The discussion centers on the mathematical definition of rotation beyond the rotation matrix, exploring various perspectives on what constitutes a rotation in a general sense. Participants examine properties of rotation matrices, particularly length preservation, and consider different conventions in defining rotations within the context of orthogonal and special orthogonal groups.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes defining rotation as elements of SO_n(ℝ), emphasizing linear maps that preserve length and orientation.
  • Another participant mentions a differing viewpoint from Fredrik, who considers O_n(ℝ) as rotations for convenience, indicating that multiple definitions exist.
  • Two conventions in the literature are noted: one where O(n) includes rotations (or orthogonal transformations) and SO(n) includes proper rotations, and another where O(n) is strictly for orthogonal transformations and SO(n) for rotations.
  • A participant provides a counterexample of a linear map in ℝ² that preserves lengths but is not a rotation, specifically the map that interchanges the x and y axes, which belongs to O(ℝ²) but not SO(ℝ²).

Areas of Agreement / Disagreement

Participants express differing views on the definition of rotation, with no consensus reached on a singular definition. Multiple competing definitions and conventions remain under discussion.

Contextual Notes

Some limitations include the dependence on definitions of rotation and the unresolved nature of which properties uniquely characterize rotations beyond length preservation.

aaaa202
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For a mathematician, how is rotation defined in the most general sense?

Question arose to me because it occurred to me that an essential property of the rotation matrix is that it preserves lengths. Is this the only mapping (if not please give me a counterexample) that has this property (identity is also a special case of a rotation of course) and can this be shown?

Might seem like a very lose question and indeed it is, so speak freely about anything that you think could improve my understanding of the fundamental mathematics behind rotation.
 
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I would personally define a rotation as everything in SO_n(\mathbb{R}). So the linear maps which preserve length and which preserve the orientation.

We had some threads about this before though. I remember Fredrik say that he would consider O_n(\mathbb{R}) as the rotations for convenience. So my answer is definitely not the only possible answer you can give.

I'll see if I can dig up some old threads.
 
micromass said:
I remember Fredrik say that he would consider O_n(\mathbb{R}) as the rotations for convenience.
I have seen at least two conventions in the literature:

1. Members of O(n) are called rotations (or orthogonal transformations), and members of SO(n) are called proper rotations.
2. Members of O(n) are called orthogonal transformations, and members of SO(n) are called rotations.

In one of those threads I said that I prefer convention 1. Lately I've been thinking that I prefer convention 2.
 
aaaa202 said:
For a mathematician, how is rotation defined in the most general sense?

Question arose to me because it occurred to me that an essential property of the rotation matrix is that it preserves lengths. Is this the only mapping (if not please give me a counterexample) that has this property (identity is also a special case of a rotation of course) and can this be shown?

Might seem like a very lose question and indeed it is, so speak freely about anything that you think could improve my understanding of the fundamental mathematics behind rotation.
Here is a simple concrete example in ##\mathbb{R}^2##: let ##T:\mathbb{R}^2 \rightarrow \mathbb{R}^2## be the map defined by
$$T\left(\begin{bmatrix}x \\ y \end{bmatrix} \right) = \begin{bmatrix}y \\ x \end{bmatrix}$$
i.e. we interchange the ##x## and ##y## axes. This is a linear map which preserves lengths, but it is not a rotation in the geometric sense. (There is also a "flip" involved.) Note that the matrix representation of ##T## with respect to the usual basis is
$$[T] = \begin{bmatrix} 0 & 1 \\ 1 & 0 \end{bmatrix}$$
so the determinant is -1, which shows that ##T \in O(\mathbb{R}^2)## but ##T \not\in SO(\mathbb{R}^2)##.
 

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