How Is the Area of a Floating Slab Calculated Using Buoyancy Principles?

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SUMMARY

The area of a floating slab can be calculated using buoyancy principles, specifically Archimedes' principle. When a swimmer of mass m rests on a plastic slab with thickness h and density p_s, the equilibrium of forces leads to the equation Mg = p_w * g * V, where V is the volume of the slab. By substituting V with h * A, the area A can be derived as A = (M + m) / (p_w * h), ensuring all variables are included. This approach effectively balances the mass of the slab and the swimmer to yield a comprehensive formula for area calculation.

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walker
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Question is: A plastic slab has a thickness of h and a density p_s . when a swimmer of mass m is resting on it, the slab floats in fresh water with its top at the same level as the water surface. find the area of the slab. give your answer in terms of density of water p_w , p_s , h and m

so what I've done is used achimedes principle where all forces are in equilibrium. that is B = Mg

M being the mass of the swimmer and slab of plastic combined

so by setting this equation equal to the buoyancy force in terms of pressure I get: Mg = p_w*g*V where p_w is the density of fresh water and since V equals h*A I can sub for V and get Mg = p_w*g*h*A then i can just solve for A but the answer A = M/(p_w*h) doesn't use all the terms given in the question. am i just reading into the question too much or am i missing something here?
 
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I got an answer by setting up two equations:

find a statement for the mass of the slab using its density, h and the unknown area.

Find another statement for the mass of the slab using the equation you have above (but call the combined mass "M+m" with M being the mass of the slab).

With two terms for the mass of the slab, set them equal to each other so that M goes away. Then do some algebraic gymnastics and you get an answer with the proper variables.
 

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