How is the Barrel Length of a Human Cannon Calculated?

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Homework Help Overview

The discussion revolves around calculating the barrel length of a human cannon based on the impulse experienced by the cannonball. The subject area includes concepts of impulse, force, and energy in the context of physics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of force using impulse and explore the relationship between force, displacement, and kinetic energy. There is uncertainty regarding the appropriate formulas to use for determining the barrel length.

Discussion Status

Some participants have provided guidance on using work-energy principles to approach the problem. Multiple interpretations of the calculations and methods are being explored, particularly concerning the application of formulas related to kinetic energy and impulse.

Contextual Notes

Participants are working under the assumption that the force is applied only during the time the cannonball is in the cannon. There is a focus on significant figures in the final answer for the barrel length.

Mary1910
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Human cannonballs have been a part of circuses for years. A human cannonball with a mass of 70kg experiences an impulse of 4.0 x 10^3 N•s for 0.35 s.

a) Calculate the force acting on the human cannonball.

F=(J)/(Δt)
=(4000 N•s)/(0.35s)
=11428.5 N
=1.14 x 10^4 N

b)How long was the barrel of the cannon?(Assume the force is applied only for the period of time that the cannonball is in the cannon.)

Im not to sure about part b), At first I thought that I should be using F•d=ΔEk, but I don't think so. Although I don't think I know of any other formulas for this type of problem that would incorporate displacement.

Any help would be appreciated. Thank you.
 
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Mary1910 said:
Human cannonballs have been a part of circuses for years. A human cannonball with a mass of 70kg experiences an impulse of 4.0 x 10^3 N•s for 0.35 s.

a) Calculate the force acting on the human cannonball.

F=(J)/(Δt)
=(4000 N•s)/(0.35s)
=11428.5 N
=1.14 x 10^4 N

b)How long was the barrel of the cannon?(Assume the force is applied only for the period of time that the cannonball is in the cannon.)

Im not to sure about part b), At first I thought that I should be using F•d=ΔEk, but I don't think so. Although I don't think I know of any other formulas for this type of problem that would incorporate displacement.

Any help would be appreciated. Thank you.
Actually that's the average force (and that's what the question should have asked you for).

Your idea was fine! Work = ΔKE seems as reasonable as any way to do this.
 
SammyS said:
Your idea was fine! Work = ΔKE seems as reasonable as any way to do this.

Thank you! Could you just let me know if this is correct?

b)

J=Δp
Δp=mΔv

4.0 x 10^3 N•s=70kgΔv
Δv=(4.0 x 10^3 N•s)/(70kg)
Δv=57m/s

Ek=½mvf^2-½mvi^2
=½(70kg)(57m/s)^2-½(70kg)(0m/s)^2
=113715-0
=1.14 x 10^5 J

F•d=ΔEk
d=(ΔEk)/(F)
=(1.14 x 10^5)/(1.14 x 10^4)
=10m

Therefore the barrel of the cannon is 10m :smile:
 
Yes, with significant digits, it's 10m or arguably it's 10.0m
 
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