How Is the Initial Momentum of a 2kg Block Determined After Explosion?

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SUMMARY

The initial momentum of a 2 kg block, which explodes into two fragments, is calculated using the principle of conservation of momentum. The first fragment, weighing 1.2 kg, moves east at 10 m/s, while the second fragment, weighing 0.8 kg, moves at 22 m/s at an angle north of west. The correct initial momentum of the 2 kg block is 13 kg m/s, as the horizontal components of the fragments' momentum cancel each other out, leaving only the vertical component from the second fragment to contribute to the total momentum.

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Homework Statement



A 2 kg block moves north at an unknown velocity. It then explodes into two blocks, the first one being 1.2 kg and moves EAST at 10 m/s, the second one is 0.8 kg and moves 22 m/s at an angle North of West.

What is the initial MOMENTUM of the 2kg block?

Homework Equations



p initial = p final (momentum conserved)

The Attempt at a Solution



The answer i got was 13 kg m/s, and some friends of mine got 29.6 kg m/s. The reason i got 13 is because I think/thought the two horizontal components of the exploded blocks cancel out each other because they are in separate directions (velocity is a vector and therefore one being negative one being positive, so I thought only the vertical component of the second block's momentum mattered).

Any help is appreciated Thank You!
 
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