How Is the Sliding Distance of a Block Calculated After a Bullet Embeds Into It?

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SUMMARY

The sliding distance of a block after a bullet embeds into it can be calculated using the principles of conservation of momentum and kinetic friction. The initial velocity of the block and bullet system after the collision is derived from the equation \( V = \frac{m \cdot V_o}{m + M} \). The distance \( s \) that the block slides before coming to rest is expressed as \( s = \frac{V^2}{2Ug} \), where \( U \) is the coefficient of kinetic friction and \( g \) is the acceleration due to gravity. The final formula incorporates the masses of the bullet and block, the initial velocity of the bullet, and the frictional force acting on the system.

PREREQUISITES
  • Understanding of conservation of momentum in collisions
  • Knowledge of kinetic energy and potential energy equations
  • Familiarity with the concept of kinetic friction
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of conservation of momentum in elastic and inelastic collisions
  • Learn about the derivation and applications of kinetic friction coefficients
  • Explore energy conservation principles in mechanical systems
  • Investigate real-world applications of bullet penetration and block motion dynamics
USEFUL FOR

Students in physics, engineers working on impact analysis, and anyone interested in the dynamics of collisions and motion involving friction.

anelmarx
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Homework Statement



Consider a bullet of mass m fired at a speed of Vo into a wooden blcok of mass M. The bullet instantaneously comes to a rest in the block. The block with the embedded bullet slides along a horizontal surface with a coefficient of kinetic friction U.
How far does the block slide before is comes to rest; find s.
Express answer in terms of m,M,Vo,U and g.

Homework Equations



KE=PE

The Attempt at a Solution



1/2(m+M)V*V=(m+M)gs*U
so
s=V*V/2Ug

I think that is correct , but now my answer does not have Vo,m,M?
("Express answer in terms of m,M,Vo,U and g.")
 
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anelmarx said:
Consider a bullet of mass m fired at a speed of Vo into a wooden blcok of mass M. The bullet instantaneously comes to a rest in the block. The block with the embedded bullet slides along a horizontal surface with a coefficient of kinetic friction U.
How far does the block slide before is comes to rest; find s.
Express answer in terms of m,M,Vo,U and g.

Hi anelmarx! :smile:

Use conservation of momentum (it's conserved in all collisions) to find the velocity immediately after the collision. :wink:
 

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