How Is Thermal Energy Produced in a Resistor During Capacitor Discharge?

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Homework Help Overview

The discussion revolves around understanding the production of thermal energy in a resistor during the discharge of a capacitor. Participants are exploring the relationship between the energy stored in the capacitor and the energy dissipated in the resistor, particularly focusing on the rate of thermal energy production.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the correct interpretation of the energy discharge from the capacitor and its relationship to the thermal energy produced in the resistor. There are attempts to relate the discharge equation to the energy entering the resistor, with some confusion about the mathematical representation of decay and growth in the context of energy transfer.

Discussion Status

The discussion is active, with participants providing insights into the nature of thermal energy production in resistors connected to discharging capacitors. Some guidance has been offered regarding the formulas for power dissipation, but there is no explicit consensus on the correct approach yet.

Contextual Notes

There is an emphasis on the importance of the specific conditions of the circuit, such as whether the resistor is connected to a discharging capacitor or a constant voltage source, which affects the thermal energy production over time.

Daniiel
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I have a quick question.
part of one of my questions asks
"Find the rate at which thermal energy is produced in a resistor"
i havn't included the whole question because i don't think it matters, its just like the last part of it
so we have
http://edugen.wiley.com/edugen/courses/crs1650/art/math/halliday8019c27/math148.gif
thats the discharge of energy out of the capacitor
so
would the inverse of that be the rate at which the energy is moved into the resistor
like
1/u = 2ce/q (i left out a lot of things but thatsl ike the base of it)

orr
do you juts switch the e^- to e^+
because e^- is decay and e^+ is growth

yeh I am just abit confused which is right, or if either is right haha.
thanks
 
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Daniiel said:
I have a quick question.
part of one of my questions asks
"Find the rate at which thermal energy is produced in a resistor"
i havn't included the whole question because i don't think it matters,
It does matter. If the resistor is connected to the battery, thermal energy is constant with respect to time; if it is connected to a discharging capacitor (as seems to be the case here) then the thermal energy will be a function of time.
its just like the last part of it
so we have
http://edugen.wiley.com/edugen/courses/crs1650/art/math/halliday8019c27/math148.gif
thats the discharge of energy out of the capacitor
No. That's the energy stored in the capacitor at any time t.
so
would the inverse of that be the rate at which the energy is moved into the resistor
like
1/u = 2ce/q (i left out a lot of things but thatsl ike the base of it)

orr
do you juts switch the e^- to e^+
because e^- is decay and e^+ is growth

yeh I am just abit confused which is right, or if either is right haha.
thanks
None of the above. The rate at which energy is dissipated in the resistor (i.e. power dissipated) is given by
P = i2R, where i is the current in the resistor at a given time t. That's what you need to find an expression for.
 
what about
P(t)= V(t) I(t)
is that alright aswell?
 
Yes it is, but you will have to find two functions of time, V(t) and I(t). If you use P = I2R, you will need only I(t).
 

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