How Is Voltage Across a Resistor Equivalent to That Across a Capacitor?

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mcpoopants
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Alright, so there is a very basic theory involving capacitors and electric potential that is throwing me off. I have a very basic problem here: http://img444.imageshack.us/img444/2251/73619554.png

Assume the switch is closed and the capacitor is fully charged. From here I'm prompted to find the final voltage across the capacitor. Pretty obvious, you use V=IR, but I'm missing out on the value of "R". In this problem it is just R2, which is given to you. My problem is that I do not understand how the voltage across that resistor is equivalent to the voltage across that fully charged capacitor. It'd really help to explain as slowly as possible, because it is a basic idea that is kicking my butt in more complicated problems. Thanks to all.
 
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Use kirchhoffs loop rule around R2 and the capacitor. When you move from a point in a circuit, back to the same point, the net voltage change must be zero. This is the same thing as saying that the voltage difference between a point and itself is zero.

So, if a point on the top wire---between the resistor and capacitor---has a given voltage difference from a point on the bottom wire---between the resistor and cap---across the resistor, it has to be the same as across the capacitor... because they're the same two points.

Does that make any sense?