How Is Voltage Induced in a Rotating Coil Within a Magnetic Field?

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SUMMARY

The discussion focuses on calculating the induced peak voltage in a circular coil with a radius of 10 cm and 25 turns, rotating in a magnetic field of strength 2.4 T at a frequency of 50 Hz. The induced peak voltage is determined using the formula V = -N * B * A * ω * sin(θ), resulting in a value of approximately 592.177 V when the coil is perpendicular to the magnetic field. The time-dependence of the induced voltage is confirmed to resemble a sine wave. Additionally, the right-hand rule and Lenz's Law are essential for understanding the direction of rotation of the coil.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with the right-hand rule and Lenz's Law
  • Basic knowledge of angular frequency (ω) calculations
  • Ability to calculate area (A) of a circle
NEXT STEPS
  • Study the derivation and applications of Faraday's Law of Electromagnetic Induction
  • Learn about the right-hand rule and its applications in electromagnetism
  • Explore Lenz's Law and its implications in induced currents
  • Investigate the relationship between frequency and induced voltage in AC circuits
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the principles of induced voltage in rotating coils within magnetic fields.

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Homework Statement



1.A circular coil, with radius of 10 cm, and 25 turns, rotates in a constant magnetic field of
strength 2.4 T, with the axis of rotation perpendicular to the direction of the magnetic
field.

A. If the coil rotates at a frequency of 50 Hz, what is the induced peak voltage?
B. Sketch the time-dependence of the induced voltage.
C. If the magnetic field that the coil is in points down the page, which direction does the coil rotate? Answer for both cases: (1) q traveling from left to right and (2) q traveling from right to left in the coil.

Homework Equations



V = -N * [ dΦ / dT ]
Φ = B * A * cosθ

V = -N * B * A * ω*sinθ
ω = 2π*f

The Attempt at a Solution



A. A = π*.1^2
.031416 m^2

ω = 2π*50
314.159 rad/s

peak voltage would occur when the coil is perpendicular to the magnetic field correct? So would I put π/2 in for sin(x) and get the following?
V = 25 * 2.4 * .031416 * 314.159*sin(π/2)
1.88496 * 314.159
592.177 V
B. If A is correct, then would the time-dependence of induced emf look like a sin wave?
C. I take it I'm supposed to use the right-hand-rule and Lenz's Law for this question, but I'm slightly confused as to how to go about doing so
 
Last edited:
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bump, I believe A and B are correct from what I understand, but I'm still having trouble with C.
 
I need help with this question too.
 
Yeah, I don't understand how to use the 50Hz to determine the peak voltage. I really hate this class! None of this was taught in the lesson or explained at any point. An explanation of the equations would be helpful. Please, anyone?
 

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