How Is Work Calculated for a Constantly Moving Elevator?

[pookisantoki]

A cable lifts a 1260-kg elevator at a constant velocity for a distance of 42.3 m. What is the work done by (a) the tension in the cable and (b) the elevator's weight?

For part a.) w=(Fcos(theta))s
w=(fcos(0))s
=fs and s= 42.3

part b.) Fcos(theta))s
w=(fcos(180)s
=-fs and s= 42.3
BUt how do i find F? and is this the right set up??

 

[turin]

BUt how do i find F? and is this the right set up??

How did you find theta in each case? In order for you to decide what is theta, should should have had an idea what was the F.