How is Work Related to Velocity?

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Homework Help Overview

The discussion revolves around the relationship between work and velocity in the context of physics. The original poster presents a problem involving work defined as an integral of force with respect to displacement, where force is expressed as a function of velocity. The problem also includes equations for acceleration and the dynamics of an object influenced by various forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the integral of force as a function of velocity and discuss the implications of different forces acting on the object. Questions arise regarding the definitions of acceleration and the relationship between net force and external forces.

Discussion Status

The discussion is active with participants seeking clarification on the relationships between the forces involved and how they relate to the calculation of work. Some participants have offered hints and references to relevant formulas, while others are questioning the setup and definitions provided by the original poster.

Contextual Notes

There are indications of confusion regarding the number of forces acting on the object and the specific force for which work is being calculated. The original poster is encouraged to clarify the problem statement to facilitate more effective assistance.

Eeeff
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Homework Statement


Help. If
w = ∫F dx
where w is work, f is force and x is displacement, and also
F = k1v2
where force is a quadratic function of velocity v times a constant k1,
what would be work with regards to velocity?

Homework Equations


More info if needed.
v = ∫a dt
a = k2 - k1v2/m
k2 is another constant representing the initial acceleration, and m is the mass of the object.

The Attempt at a Solution


I have some attempts but I am just clueless.

Thanks.
 
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I have an idea.F is a funtion of v so W=∫F(v)dx the main purpose should be solve this integral but for that it must be in the same "thing".Like ∫tdt or ∫vdv etc.
Using a = k2 - k1v2/m and some equations you can find it.
 
Eeeff said:
a = k2 - k1v2/m
I don't see where you got this. If F = ma and F = k1v2, what is a?
 
There is a very useful formula for when you don't care about the time of the motion:
##a=\frac{dv}{dt}=\frac{dx}{dt}\frac{dv}{dx}=v\frac{dv}{dx}##.
 
There is also the work-kinetic energy theorem.
 
kuruman said:
I don't see where you got this. If F = ma and F = k1v2, what is a?
Let me clarify, Fext = k1v2. Fnet = ma = mk2 - Fext.
 
Eeeff said:
Let me clarify, Fext = k1v2
Fnet = ma = mk2- Fext
 
Last edited:
Eeeff said:
Let me clarify, Fext = k1v2. Fnet = ma = mk2 - Fnet.
How many forces are there? If there is only one, the net force, i.e. the sum of all the forces, is that one force.
 
kuruman said:
How many forces are there? If there is only one, the net force, i.e. the sum of all the forces, is that one force.
Sorry for not making this clear. There is forceext1 = k1v2 that is acting against the object and constant forceext2 = mk2 acting on the object.
 
  • #10
Eeeff said:
Sorry for not making this clear. There is forceext1 = k1v2 that is acting against the object and constant forceext2 = mk2 acting on the object.
OK. The work done by which force is the question asking you to calculate?

I know you are new to PF, but for future reference, please post the problem exactly as it is given to you. It will avoid misunderstandings and your question will be answered more quickly.
 
  • #11
kuruman said:
OK. The work done by which force is the question asking you to calculate?

I know you are new to PF, but for future reference, please post the problem exactly as it is given to you. It will avoid misunderstandings and your question will be answered more quickly.
I wish to know the work done by F ext1. Anyway, why would I want to know the force done by the constant force, when it is just W = Fd.
 
  • #12
Eeeff said:
Anyway, why would I want to know the force done by the constant force, when it is just W = Fd.
It's not what you want to know, it's what the problem is asking you to answer. Actually, for this problem, finding the work done by the constant force is part of the answer. You can use the hint provided by haruspex (post#4) or by me (post #5); they are basically the same idea for tackling the problem.
 

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