How Likely Is More Than Two Successes in Six Trials with 10% Success Rate?

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The discussion focuses on calculating the probability of achieving more than two successes in six trials with a success rate of 10%. The formula used is P(x > 2) = 1 - P(x ≤ 2), where P(x ≤ 2) is computed using the binomial probability formula. The conversation emphasizes the importance of understanding the underlying concepts rather than seeking step-by-step solutions. Participants are encouraged to engage critically with the problem rather than relying solely on others for answers.

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given trails n = 6, success probability p = 0.1



radou said:
[tex]P(x > 2) = 1 - P(x \leq 2)[/tex]
[tex]P(x \leq 2) = \left( \begin{array}{c} 8 \\ 0 \end{array} \right) 0.3^0 (1-0.3)^{8-0} + \cdots[/tex] (sum until x = 2, including that case)

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First, do not post same questions. Second, if you expect someone to solve the whole problem step by step (i.e. number by number), then you might be in the wrong forum. Third, without using your head, you won't solve any problem. Fourth, I'm not being rude.
 
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