How Long Did the Power Delivery to the Ball Last?

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a 5 kg ball tossed into the air with an initial velocity of 6 m/s. Participants explore the concepts of kinetic energy and power delivery, specifically focusing on calculating kinetic energy and determining the time interval for power delivery.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of kinetic energy using the formula K.E = 1/2 mV² and question whether the initial velocity can be directly used in the equations provided. There is also a mention of confusion regarding the relationship between initial velocity and the velocity used in calculations.

Discussion Status

The conversation includes confirmations of calculations and expressions of confusion regarding the application of initial velocity in the kinetic energy formula. Some participants have clarified their understanding, while others continue to seek clarification on the concepts of kinetic energy and power.

Contextual Notes

Participants are navigating the definitions and applications of kinetic energy and power, with some expressing difficulty in these areas. There is an emphasis on understanding the relationship between initial velocity and the velocity used in calculations.

pinnacleprouk
Messages
26
Reaction score
0
Thanks in advance, I just want to double check!


Homework Statement



A 5 kg ball is tossed into the air with an initial velocity of 6m/s.
a) What is the kinetic energy of the ball?
b) If the power delivered to the ball was 100watts, over what time interval did
the power delivery occur?




Homework Equations



K.E = 1/2 mV*2

P = E/t



The Attempt at a Solution




a)... using K.E = 1/2 mV*2 answer is 90J

b)... using P = E/t answer is 0.9s
 
Physics news on Phys.org
Looks good!
 
But I am a bit confuesd, is initial velocity is equal to velocity in the equation?In other words, can we plug the value of initial v in v in the equation? Shouldn't we try to get velocity?
 
stanton said:
But I am a bit confuesd, is initial velocity is equal to velocity in the equation?In other words, can we plug the value of initial v in v in the equation? Shouldn't we try to get velocity?
The velocity is given. It's the velocity of the ball immediately after leaving the hand.
 
Thanks for the replies
 
Now I get it. :) Thanks! I am having difficulty with treating problems related to kinetic energy and power.
 

Similar threads

Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
14K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
9K
  • · Replies 1 ·
Replies
1
Views
3K