Here is what you did.
You converted ## 9.8 \frac {m} {s^2} ## to ## 0.00609 \frac {mile} {s^2} ##, which is a little unusual but technically correct.
Then you found that ## \displaystyle \frac { 60 \frac {mile} {hour} } {0.00609 \frac {mile} {s^2}} \cong 10000 \frac {s} {hour} s ##.
Finally, because ## \frac {s} {hour} = \frac 1 {3600} ##, you got ## 10000 \frac {s} {hour} s = \frac {1000} {3600} s ## = 2.78 s.
All of this is correct, but, as I said, is unusual. The unusuality is that you did not convert all units to one system, but kept mixed units throughout. Typically one converts all the different units to one system, then computes, and then, if required, converts to other units.
Here is how I would do it.
Convert 60 MPH to m/s. Because one mile is 1609.34 m, and 1 hour is 3600 seconds, 60 MPH = 60 * 1609.4/3600 m/s = 26.82 m/s. Now we have the velocity and the acceleration in one system of units, SI (meters and seconds), and 26.82 m/s / 9.8 m/s^2 = 2.74 s.