How Long Does It Take a Dropped Object to Hit the Ground from a Rising Balloon?

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Homework Help Overview

The problem involves a balloon ascending at a height of 81 m with a velocity of 12 m/s, from which a 2 kg object is dropped. The goal is to determine the time it takes for the object to reach the ground, given that the acceleration due to gravity is 10 m/s².

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relevance of mass in the problem and attempt to apply kinematic equations to find the time of descent. There are questions regarding the choice of coordinate system and the signs of the velocities involved.

Discussion Status

Some participants have provided insights into the importance of consistent sign conventions when applying the equations of motion. There is an ongoing exploration of different approaches to the problem, with no explicit consensus reached yet.

Contextual Notes

Participants express confusion over the initial conditions and the application of kinematic equations, indicating a need for clarification on the setup and assumptions made in the problem.

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Homework Statement



A balloon is at a height of 81 m is ascending upward with a velocity of 12 ms1. A body of 2 kg weight is dropped from it. If g = 10 ms2, the body will reach the surface of Earth in what time.


Homework Equations





The Attempt at a Solution



I don't think mass is of any importance in this question. Hence, I tried to solve it this way:

Since initial velocity = -u
(s=ut+1/2at^2)

81 = -12t+1/2*10*t^2
Solving, we have t = 42seconds.

However this is not the answer. Please explain how I solve this question.
Thanks in advance
 
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Hello physics kiddy,

physics kiddy said:

Homework Statement



A balloon is at a height of 81 m is ascending upward with a velocity of 12 ms1. A body of 2 kg weight is dropped from it. If g = 10 ms2, the body will reach the surface of Earth in what time.


Homework Equations





The Attempt at a Solution



I don't think mass is of any importance in this question. Hence, I tried to solve it this way:

Since initial velocity = -u
(s=ut+1/2at^2)

81 = -12t+1/2*10*t^2
Solving, we have t = 42seconds.

However this is not the answer. Please explain how I solve this question.
Thanks in advance

I think your signs are messing you up. You can orient your coordinate system however you want, it's up to you. But you have to pick a direction and stick to it consistently. In this case, let's choose upward to be the positive direction, and downward to be the negative direction. Then, the object's initial velocity (when dropped) is *upward*, because it is ascending along with the balloon at +12 m/s.
 
I have assumed upward to be negative and downward positive to make things easier, however, I am not getting the answer...
 
physics kiddy said:
I have assumed upward to be negative and downward positive to make things easier, however, I am not getting the answer...

Can you show the steps of your solution in more detail?
 

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