How Long Does It Take for a Police Car to Catch a Speeder?

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Homework Help Overview

The problem involves a speeder traveling at a constant speed and a police car that begins to chase from rest with a specific acceleration. The objective is to determine the time it takes for the police car to catch the speeder.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equations of motion for both the speeder and the police car, attempting to set their distances equal to find the time of the chase. There is mention of confusion regarding the application of the equations and the algebraic manipulation involved.

Discussion Status

Some participants have offered insights into potential errors in the original poster's algebraic steps, suggesting that there may have been mistakes in the manipulation of the equations. There is acknowledgment of a breakthrough in understanding after addressing these issues, though no consensus on the final solution has been reached.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is an indication of frustration with the problem-solving process, highlighting the challenges faced in understanding the concepts involved.

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Homework Statement


A speeder moving at 120km/h passes a police car that immediately begins to chase, starting from rest, with an acceleration of 1.75 m/s2. How long is the chase?
The answer is 38.1s

Homework Equations


d=v1+at2
At least that's what I tried, but it didn't work out right..,

The Attempt at a Solution


Speeder:
(In m/s)
d=33.3(t)

Police car:
d=1.75(t)2

Then attempting to equate them together:

33.3t=1.75t2
33.3t/33.3t=1.75t2/33.3t
0=0.053t
0=t

...I did something weird and it's just stopped making sense... Please help (´Д` )
 
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*1/2at2... That's might be my problem, but it's been an issue for almost an hour now (¬_¬)
 
Heres2hoping said:
*1/2at2... That's might be my problem, but it's been an issue for almost an hour now (¬_¬)
That's one problem. Here's another:
Heres2hoping said:
33.3t/33.3t=1.75t2/33.3t
0=0.053t
you seem to have subtracted on the left instead of dividing.
 
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haruspex said:
That's one problem. Here's another:

you seem to have subtracted on the left instead of dividing.
(0o0) thank you so much! I can't believe I did that (-。-; I got the right answer this time (^-^)
 

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