How long does it take for light to reach Earth in a moving rocket ship?

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Homework Help Overview

The problem involves a rocket ship moving toward Earth at a speed of 0.50c and the time it takes for light emitted from the ship to reach Earth, which is 6.00 x 10^12 m away. The context is rooted in the principles of relativity, particularly concerning the perspectives of different frames of reference.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss various approaches to the problem, including the use of basic kinematic equations and considerations of time dilation. Some express uncertainty about the relevance of Lorentz transformations and question the necessity of accounting for time dilation in this specific scenario.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have suggested simpler approaches while others have raised concerns about the need for more complex relativistic considerations. There is no explicit consensus on the correct method to apply.

Contextual Notes

Participants note a lack of access to textbooks and previous lessons on relevant concepts, which may be impacting their understanding and ability to approach the problem effectively.

justinh8
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Physics Relativity Question?

Homework Statement


A rocket ship is moving directly toward Earth with a constant speed of 0.50 c relative to Earth. It turns on its headlight, and the light beam travels toward Earth with speed c relative to the ship. According to the rocketship astronauts, Earth is 6.00 x 10^12 m away when the headlight is turned on. In the frame of the astronauts, how long does it take for the light to reach Earth? (Hint: in the frame of the astronauts, Earth is approaching the ship with a speed of 0.5c)


Homework Equations


c = 3x10^8 m/s


The Attempt at a Solution


I just got 20000 seconds but i know its wrong
 
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Can you show your working?
 


He divided 6x1012 by 3x108. I think even justinh8 knows that doesn't qualify as "an attempt at a solution".

justinh8, you haven't been following along in class. Read the appropriate chapter in your textbook on length contraction and Lorentzian Transform.
 


You need to take into account time dilation.
 


There was no lesson for this, it was just a do you remember from grade 11 physics but i do not recall any lorentzian transformations in grade 11. Plus we haven't gotten our textbooks yet so i have no clue. However, i think i know one equation that might be relevant. Its ct^2 = vt^2 + ct^2. Its from grade 11 but not sure if it would work...
 
Last edited:


justinh8 said:
There was no lesson for this, it was just a do you remember from grade 11 physics but i do not recall any lorentzian transformations in grade 11. Plus we haven't gotten our textbooks yet so i have no clue. However, i think i know one equation that might be relevant. Its ct^2 = vt^2 + ct^2. Its from grade 11 but not sure if it would work...

Hmm that's odd then. Well the equation to use is t=\frac{t'}{\sqrt{1-\frac{v^2}{c^2}}}, \text{Where } t'= \text{dilated time and } t = \text{stationary time}
 


Bread18 said:
You need to take into account time dilation.
I'm pretty sure he doesn't need to be concerned about time dilation.

Everything is given and asked in the frame of the rocket ship.
 


SammyS said:
I'm pretty sure he doesn't need to be concerned about time dilation.

Everything is given and asked in the frame of the rocket ship.

I think you're right, my mistake.
 


In which case, I think all he has to take into account is relative motions.
 
  • #10


I just talked to my teacher today and he said there is nothing to do with time dilation, he just said think simple so i think it might be using just the v= d/t and just rearrange it to find time??
 

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