How long does it take the Sun to melt a block of ice at 0°C with an area of 1.10 m2 and thickness 1.07 cm? Assume that the Sun's rays make an angle of 31.1° with the normal to the area, and that the emissivity of ice is 0.0400.
Q/t = IeAcos(theta)
The Attempt at a Solution
ok, i've done multiple attempts and am still not getting the correct answer!
1) Q/t = IeAcos(Theta)
Q/t = (1000 W/m^2)(0.04)(1.10cos(31.1)) = 37.6 J/s
but from this number, I don't understand how to find time, should it be one??
A*h *ρ *L /t = IeACOSθ
t = time for ice to melt = IeCOSθ /h *ρ *L
t = (1000 W/m^2)(0.04)(cos(31.1)/(0.0107 m)(917 kg/m^3)(3.33*10^5 J/kg)
t= 1.05*10^-5 s
but, that doesn't work either. I've been trying this problem all afternoon, please help!!