How long does it take to pour 4 liters of SAE no. 10 oil through a funnel?

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SUMMARY

The discussion focuses on calculating the time required to pour 4 liters of SAE no. 10 oil through a funnel, given its viscosity of 0.2 Pa·s and specific gravity of 0.70. The initial attempt utilized Poiseuille's law to derive the flow rate, but the resulting time of 0.03 seconds was identified as incorrect. The correct application of fluid dynamics principles, including the appropriate parameters for the funnel's dimensions and oil properties, is essential for accurate calculations.

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  • Understanding of fluid dynamics principles, specifically Poiseuille's law.
  • Knowledge of viscosity and its impact on fluid flow.
  • Familiarity with specific gravity and its calculation.
  • Basic mathematical skills for manipulating equations and units.
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Homework Statement



SAE no. 10 oil has a viscosity of 0.2 Pa· s. How long (in sec) would it take to pour 4 liters of oil through a funnel with a neck 10 cm long and 2.9 cm in diameter. Assume that it is poured in such a way that the oil level is kept just above the top of the tube.

Hint: The specific gravity (= ratio of its density to that of water) of the oil is 0.70.

The Attempt at a Solution



Dp = rgL
= (700 kg/m3)*(9.8 m/s2)*(10*0.01 m) = 686
The fow rate is given by Poiseuille's law:
Q = p r4 Dp / (8 h L)

=> t = V / Q = 8 V h L / (p r4 Dp) = 8*(4*10^-3)*0.2*(10*0.01) / (700*(0.5*2.9*0.01)^4*686 = 0.03 s = wrong answer.

Please advise! Thanks!
 
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