How Long to Fall and Speed of Impact for Object Dropped Near Moon?

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    Falling Moon
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Homework Help Overview

The discussion revolves around a physics problem involving an object dropped from a distance of 2 times the radius of the Moon. Participants are exploring how long it takes for the object to impact the Moon and the speed at which it will hit, considering the variable acceleration due to gravity.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the time of fall and impact speed using average acceleration and constant acceleration equations. Some participants suggest using integration to express velocity as a function of distance and then distance as a function of time, indicating a shift towards a more detailed mathematical approach.

Discussion Status

Participants are actively engaging with the problem, with one providing a method to derive velocity as a function of distance. The original poster has successfully calculated the impact speed but is seeking further clarification on how to determine the distance as a function of time. There is a collaborative effort to refine the understanding of the problem.

Contextual Notes

Participants are addressing the complexity introduced by the non-constant acceleration due to gravity as the object falls, which is a key aspect of the problem. The original poster's calculations are based on assumptions that may need to be revisited as the discussion progresses.

dbogen
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Homework Statement


An object is dropped from a distanse of 2*R(moon radius) from moon senter.
How many seconds does it take until impact with moon, and in what speed will it hit?

The distanse of the fall will be 1.74*10^6 m. The problem is the not so constant acceleration.. ;)

gravity constant: G := 6.67*10^(-11)
moon mass M := 0.0735^24 kg
moon radius R := 1.74*10^6 m

Homework Equations



gravity(acceleration) is
g=G*M/R^2

So a(x)=(G*M)/(2*R - x)^2 , x = meter fallen x{0..R)

The Attempt at a Solution


I've calculated the speed at impact:

Average acceleration:
> A:=(G*M)/(2*R - x)^2
> Aa := (int(A, x = 0 .. R))/R;
0.8096264368

Time using x= 0.5*a*t^2
> T := solve(R = 0.5*Aa*t^2, t);
-2073.229031, 2073.229031

This time is found using constant acceleration, so it isn't the correct one...
but it will work for finding the speed of impact.

Speed
> V := T*Aa;
-1678.541033, 1678.541033
So it will hit at 1678,54 m/s

but for how long will it fall?
 
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You have acceleration as a function of distance. Put it in the expression a = v*dv/dx.That way you can obtain velocity as a function of distance by integrating. That will solve the first part of your problem. For time you can write v as dx/dt. Now if you put that and integrate you have distance as a function of time.
 
Thanks aim!

I got the correct velocity using your method, but i don't figure out the distanse as a function of time...

Could you please try to explain it again, a bit more detailed? :)
 
Ok you figured out velocity as a function of distance(x). Now what you do is write v as dx/dt. You will notice that the equation now contains x and t only. A little rearrangement and integration and you can express x as function of t.
 

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