How Long Until a Radioactive Daughter Isotope Reaches 97% of Its Equilibrium?

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Homework Help Overview

The problem involves a parent radioactive isotope with a specified half-life that decays into a series of daughter isotopes, one of which has the longest half-life. The original poster seeks to determine the time required for the daughter isotope with the longest half-life to reach 97% of its equilibrium value, given that the parent isotope starts with a certain number of nuclei and no daughters are initially present.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the differential equation governing the decay process and question whether the decay of other daughter isotopes needs to be considered. There is also a discussion about the specific half-lives of the isotopes involved and how they affect the calculations.

Discussion Status

Participants are exploring the relationships between the decay rates of the parent and daughter isotopes and how these affect the time to reach equilibrium. Some guidance has been offered regarding the equations to use, but there is no explicit consensus on the approach or final calculations.

Contextual Notes

There is mention of the half-lives of the isotopes involved, with the longest daughter half-life being 20 years and the parent half-life being 10,000 years. The discussion includes considerations of decay rates and the implications of multiple daughter isotopes in the decay chain.

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Homework Statement


A parent isotope has \tau_\frac{1}{2}=\delta. Its decays through a series of daughters to a final stable isotope. One of the daughter particles has the greatest half life of \tau_\frac{1}{2}=\alpha-- the others are less then a year. At t=0 the parent nuclei has N_0 nuclei, no daughters are present.

How long does it take for the population with the greatest half life to reach 97% its equilibrium value?
At some t, how many nuclei of the isotope with the greatest half life are present, assume no branching.


Homework Equations


\frac{dN}{dt}=e^{-\lambda t}


The Attempt at a Solution


So for the first one:
Its just solving the diff eq above right? The daughter is in its eq. value or do we have to worry about decay from the other daughters?

the second one:
Basically plugging in t right for the solved diff eq with initial nuclei right?

Just checking, I feel like I'm missing something.
 
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Hi there,

You have the right equation: \frac{dN}{dt} = e^{-\lambda t} But don't forget that the daughter nuclei also decay at a certain rate. Therefore, you need to consider the same equation for the long life daughter nucleus.

By the way, just a further comment, typically what half-life are you talking about here? Because, daughter nuclei with half-life of more than a few split second are normally considered into the decay chain.

Cheers
 


the halflife(longest) for the daughter is 20yr. The parent is 10^4 yr.
So for the daughter nuclei(20 yr):
<br /> \frac{dN}{dt} = e^{-\lambda_1 t}- e^{-\lambda_2 t}<br />
Where 2 is the daughter. Should 1 be the half life of the 1yr daughter?
 


Hi there,

When the equilibrium is reach, the decay rate of the parent nuclei is the same as the decay rate of the daughter nuclei, and it is independent of the daughters formed in the process. Therefore, you would have: \frac{dN_1}{dt} = \frac{dN_2}{dt}

If you solve this simple equation, you have the time needed to reach equilibrium.

Cheers
 


Hi there,

Your question really caught my attention, and with the half lives you gave me, I find that the system will reach equilibrium after 138.2 years.

Cheers
 

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