MHB How long will it take for the jets to be 9128 miles apart?

  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Jets
Click For Summary
Two jets depart simultaneously, one flying at 377 mph and the other at 275 mph, heading in opposite directions. To determine how long it will take for them to be 9128 miles apart, the equation 377t + 275t = 9128 is set up, where t represents time. This equation combines the distances covered by both jets over time. The discussion confirms the correctness of the equation and suggests using 't' instead of 'x' for clarity. The focus remains on calculating the time required for the jets to reach the specified distance apart.
mathdad
Messages
1,280
Reaction score
0
Two jets leave an airport at the same time, flying in opposite directions. The first jet is traveling at three hundred seventy-seven mph and the other at two hundred seventy-five mph. How long will it take for the jets to be 9128 miles apart?

My Effort:

Jet 1:

rate = 377 mph

time = x

Distance = 9128 miles

Jet 2:

rate = 275 mph

time = x

Distance = 9128 miles

Equation:

377x + 275x = 9128

Is this correct?
 
Mathematics news on Phys.org
yes ... I would have used $t$ for time instead of $x$
 
It feels so good to get it right. Ok. I got it. Let t replace x for time.