How Long Will It Take to Heat Water in an Electric Kettle?

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Homework Help Overview

The discussion revolves around calculating the time required to heat a specific mass of water in an electric kettle using given electrical parameters. The subject area includes thermodynamics and electrical power calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between power, energy, and heat, questioning whether heat (Q) and electrical energy (E) can be treated similarly in calculations. There is discussion on the correct use of formulas and units related to power and energy.

Discussion Status

Some participants have provided guidance on the relationships between different forms of energy and their units. There is a mix of interpretations regarding the calculations, with one participant presenting a detailed calculation attempt while others focus on clarifying concepts and units.

Contextual Notes

Participants reference a previous thread for additional context and clarification, indicating that this problem may be a common type encountered in homework assignments. There is an emphasis on ensuring clarity in calculations and understanding the underlying principles.

chawki
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Homework Statement


In an electric kettle with good heat insulation 0.85 kg water is warmed by an electrical resistance of 25 Ohms, which is connected to a voltage of 230 V. The specific heat capacity of water is 4190 J/(kg°C)

Homework Equations


In what time will the temperature of the water rise by 20 °C?

The Attempt at a Solution


P=E/t
but here we can calculate only Q
are they the same?
 
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Compare the units. One is a rate, the other is an amount.
 
Power is Joules/second. Heat is Joules. One is a rate, the other an amount.
 
Yes, i was meaning Q and E
i was meaning if we can write P=Q/t anstead of P=E/t...because both Q and E are energies and joules.

This is how i solved it..
Q=m*Cp*delta T
Q=0.85*4190*20
Q=71230 J

then we calculate P
P=V2/R
P=2302/25
P=2116 watt

P=Q/t
t=Q/P
t=71230/2116
t=33.66 seconds ?
 
Forms of energy are interconvertible under the appropriate circumstances. Certainly electrically produced heat energy can be used to add heat to physical substances.
 
Is my answer and the way i have written it correct ?
 
chawki said:
Is my answer and the way i have written it correct ?

Sure. Well done. Although if you have time, you should annotate the calculations a bit to explain what it is you're calculating in each section. It's a bit like writing good computer code... imagine that someone who has never seen it before needs to understand it in a hurry.
 
Thank you gneill o:)
 

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