The discussion centers on calculating the number of oxygen atoms in 300 grams of calcium carbonate (CaCO3). The molar mass of CaCO3 is established at 100 grams per mole. To find the number of oxygen atoms, one must first determine the number of moles in 300 grams, which is 3 moles. Since each molecule of CaCO3 contains 3 oxygen atoms, the total number of oxygen atoms is 3 moles multiplied by Avogadro's number (6.022 x 10²³), resulting in approximately 5.43 x 10²⁴ oxygen atoms.
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Have you studied the concept of the mole in chemistry?NeerajKarthi said:Homework Statement
How many atoms of oxygen are present in 300 grams of calcium carbonate?
molar mass of CaCO3 = 100g
Homework Equations
The Attempt at a Solution
I don't know how to proceed.
Can anyone please help me out by giving the forulae or steps on how to do this problem.